C#
2017.12.17 23:44
HTTP로 JSON을 받아와서 ListView에 표시하는 샘플
조회 수 102275 추천 수 0 댓글 0
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;
using Newtonsoft.Json.Linq;
using System.Net;
using System.IO;
namespace ListViewSample
{
/// <summary>
/// MainWindow.xaml에 대한 상호 작용 논리
/// </summary>
public partial class MainWindow : Window
{
public MainWindow()
{
InitializeComponent();
}
private void Refresh_Button_Click(object sender, RoutedEventArgs e)
{
string json = this.Request_Json();
this.ParseJson(json);
}
private string Request_Json()
{
string result = null;
Console.WriteLine("url : " + url);
try
{
HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
HttpWebResponse response = (HttpWebResponse)request.GetResponse();
Stream stream = response.GetResponseStream();
StreamReader reader = new StreamReader(stream);
result = reader.ReadToEnd();
stream.Close();
response.Close();
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
return result;
}
private void ParseJson(String json)
{
List<Issue> issues = new List<Issue>();
JObject obj = JObject.Parse(json);
JArray array = JArray.Parse(obj["issues"].ToString());
foreach (JObject itemObj in array)
{
Issue issue = new Issue();
issue.Subject = itemObj["subject"].ToString();
issue.Done = itemObj["done_ratio"].ToString();
issue.Author = itemObj["author"]["name"].ToString();
issues.Add(issue);
}
IssueListView.ItemsSource = issues;
}
private void Clear_Button_Click(object sender, RoutedEventArgs e)
{
IssueListView.ItemsSource = null;
}
}
}
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